Nuprl Lemma : fpf-join-ap-left 11,40

A:Type, B,C:(AType), eq:EqDecider(A), f:fpf(Aa.B(a)), g:fpf(Aa.C(a)), x:A.
(fpf-dom(eqxf))  (fpf-ap(fpf-join(eqfg); eqx) = fpf-ap(feqx B(x)) 
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Definitionsx:AB(x), x(s), P  Q, fpf-ap(feqx), fpf-join(eqfg), t.2, fpf-cap(feqxz), if b then t else f fi , t  T, tt, xt(x), ff, prop{i:l}, , Unit, P  Q, P  Q, A, False,
Lemmasfpf-dom wf, bool wf, eqtt to assert, fpf-ap wf, iff transitivity, assert wf, bnot wf, not wf, eqff to assert, assert of bnot, fpf-trivial-subtype-top, fpf wf, deq wf

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